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(Refer Slide Time: 49:24) So, for the axial turbine, we have alpha 2 and beta 3 as 60 degrees; alpha 3 and beta 2 as 0 degrees; specific work for this case, in this fifty percentage reaction case, would be U times delta C w; U times C w 2 and C w 3. Here as you can see, C w 3 would be equal to 0 for the axial turbine because the flow is leaving in the axial direction. So, C w 3 is 0 and C w 2 is equal to U 2. C w 2 is the tangential component of C 2, which is equal to U 2. And therefore, the specific work done for the axial turbine would be simply U square. For the radial turbine, alpha 2 and beta 3 are 60 degrees; beta 2 and alpha 3 are equal to 0. And, specific work done is U 2 C w 2 minus U 3 C w 3. In this case of course, C w 3 is again 0, like in the case of axial turbine. And, C w 2 is at the inlet, is equal to U 2. And, of course at the exit U 2 and U 3 are not the same. But, since C w 3 is 0, the radial turbine also develops a work which is equal to U square. In this case it is, U 2 square. So, specific work done in this particular case one of them is for an axial turbine and other is for radial turbine. For given these conditions for the same rotational speed, both of these turbines generate the same work output. They both are functions of square of the blade speed. So, in this specific case that for example, that we have looked at because of the conditions that have been specified to us for the same blade angles and rotational speeds, both these turbines generate the same work output. So, just to give you an idea of how the work done can be calculated for different types of turbine configurations, of course,PDF Image | Turbomachinery Aerodyanmics
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