Turbomachinery Aerodyanmics

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Turbomachinery Aerodyanmics ( turbomachinery-aerodyanmics )

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Now, the third part of the question is to find the Mach number and then, we should also need to find the blade speed at the tip of the rotor. So, we will first find the absolute Mach number at the inlet, for which we will find first the Mach number corresponding to stagnation conditions. (Refer Slide Time: 41:26) So, M 0 2, this again is coming from the very basic definition for delta M 0 2 square is equal to delta W by gamma minus 1 into 2 cos beta 2 by 1 plus cos beta 2. Now, where does this equation come from? Again I will urge you to try to derive this equation from the fundamentals. Delta W is h 0 1 minus h 0 3, which is m dot C p into T 0 1 minus T 0 3. And, there the temperatures can actually be expressed in terms of the corresponding velocities. And therefore, we can express the Mach number in terms of the, well, part of the temperature get expressed in terms of Mach number, wherein this flow angles alpha 2 and beta 2 will also come into picture. So, from those fundamental equation we can actually derive the stagnation Mach number, which is M 0 2 Mach number at the inlet of the rotor, M 0 2 square is delta W by gamma minus 1 into 2 cos beta 2 by 1 plus cos beta 2. So, all the parameters on the right hand side are known to us. We just, substitute these different values and we get M 0 2 is 0.7389. The absolute Mach number which is basically based on this static conditions, M 2 is related to M 0 2 as we know. So, M 2 square is M 0 2 square by 1 plus gamma minus 1

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