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Also, another consequence of the Whitfield’s equation is that, we have beta 2 is equal to 2 into 90 minus alpha 2. Beta 2 is the blade angle at the inlet of the rotor. And, that is equal to 2 into 90 minus alpha 2. And, so this comes to be 33.56 degrees. (Refer Slide Time: 39:26) So, the next part of the question is to find the pressure ratio, well, basically the total-to- static efficiency. And, for which, of course we will use the total-to-static efficiency basically is T 0 1, 1 minus T 0 3 by 3, T 0 1 minus T 3 or T 3 s. And, from there we can express the denominator in terms, P 3 by P 0 1. And, in this question, we know that the power developed is given as 230 kelvin, inlet stagnation temperature is given, mass flow rate is given and the total-to-static efficiency is given. So, we need to find the pressure ratio in this case. So, all we have do is, we just substitute the power output here, which is m dot into C p into delta T. C p is known, assumed and the stagnation temperature is also can be calculated or it is given at the inlet. Since the efficiency is known, we can calculate the pressure ratio, P 3 by P 0 1 as 0.32165. The inverse of this is the turbine pressure ratio, which is P 0 1 by P 3 and that is 3.109. So, this basically comes from the efficiency definition eta T s is T 0 1 minus T 0, T 0 3 divided by T 0 1 minus T 3 s. The denominator gets expressed in terms of the pressure ratio, from the isentropic relation numerated is simply C p times delta T. And therefore, that is the power output of the turbine.PDF Image | Turbomachinery Aerodyanmics
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